Question 1153164
This is a binomial with n=12 p=0.27
for exactly 3, it is 12C3*0.27^3*0.73^9=0.2549

at least 4, find 0,1,2
0 is .73^12=0.0229
1 is 12*.27*.73^11=0.1016
2 is 66*.27^2*.73^10=0.2068

The sum of 0,1,2,3 [probabilities above is 0.5862
So at least 4 is 1-0.5862 or 0.4138

for 8: prob =0.0040
for 9: prob=0.0007
for 10: prob=0.00007 or 0.0001
11 and 12 are too small to consider
probability 8 or more is 0.0048

probability fewer than 8 is the complement or 0.9592