Question 1153059


The base of a triangle is 4 inches more than 2 times the height. 

=>{{{b=2h+4}}}....eq.1

If the area is {{{8}}} square inches, 

{{{A=(1/2)bh}}}

{{{8=(1/2)(2h+4)h}}}

{{{8=(h+2)h}}}

{{{h^2+2h-8=0}}}

{{{(h - 2) (h + 4) = 0}}}

=> solutions: {{{h=2}}} or {{{h=-4}}}-> since height, disregard negative solution

so, {{{h=2}}}

go to eq.1

{{{b=2h+4}}}....eq.1, substitute {{{h}}}

{{{b=2*2+4}}}

{{{b=8}}}

answer: the base is {{{8}}} and the height is {{{2}}}