Question 1152966
<br>
Here is a very different non-algebraic way for solving many kinds of problems similar to this one.<br>
All $5000 invested at 7% would yield $350 interest; all at 9% would yield $450 interest.<br>
Use any method you want to determine that the actual interest of $390 is "40/100 = 2/5 of the way from $350 to $450".<br>
That means 2/5 of the money was invested at the higher rate.<br>
ANSWER: 2/5 of the $5000, or $2000, at 9%; $3000 at 7%<br>
CHECK: .09(2000)+.07(3000) = 180+210 = 390<br>