Question 1152863
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The ratio initially is A:B:C = 3:4:5, with B having 48 sweets.<br>
Any number of different calculations can be done to determine that A has 36 sweets and C has 60 sweets; and the total number of sweets is 144.<br>
After C shares some of his sweets with A and B, the ratio is supposed to be A:B:C = 12:16:15.<br>
But 144 sweets can't be divided in the ratio 12:16:15 -- so the problem is flawed.<br>
If the ratio shown at the end of the problem is correct, then C didn't share any of his sweets with his brothers -- he simply ate some of his.<br>
{{{12x+16x+15x = 43x}}}<br>
x has to be an integer for which 43x is less than 144; the maximum value is 3.  That means the numbers of sweets are now 36, 48, and 45.<br>
So A and B still have the numbers they started with; and C has 15 fewer.<br>
And since I don't think he would have thrown them away, my guess is he ate them....<br>