Question 1152876


Solve the equation:

{{{3(2^(2x+2))-5(2^(x+2))=0}}}.............since {{{2^(2x+2)=2^x*2^(x+2)}}}, we have

{{{3(2^x*2^(x+2))-5(2^(x+2))=0}}}.....both sides divide by {{{2^(x+2)}}}

{{{3(2^x)-5=0}}}

{{{3(2^x)=5}}}

{{{2^x=5/3}}}

{{{log(2^x)=log(5/3)}}}

{{{x*log(2)=log(5)-log(3)}}}

{{{x=(log(5)-log(3))/log(2)}}}