Question 1152836
Question is a little unclear.  Resize by area, or resize by linear dimensions?


If by AREA is meant, then
{{{24(4/3)=32}}} square inches


{{{(4+x)(6+x)=32}}}
{{{x^2+10x+24=32}}}
{{{x^2+10x=8}}}
{{{x^2+10x-8=0}}}


{{{x=(-10+- sqrt(100+4*8))/2}}}

{{{x=(-10+- sqrt(132))/2}}}

{{{x=(-10+- 2*sqrt(33))/2}}}

{{{x=-5+- sqrt(33)}}}

{{{highlight_green(x=-5+sqrt(33))}}}
This x value is about 0.7446 inches.
Very nearly {{{3/4}}} inch increase in each dimension.


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New Width  about {{{4&3/4}}} inches
New Length about {{{6&3/4}}} inches
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