Question 1152830


If {{{dy/dx=6x^2+4x-5}}}, then {{{f(x)}}} is

 {{{y=2x^3+2x^2-5x}}}


and {{{y=10}}} when {{{x=2}}}, 

let'c double check that: 

{{{y=2*2^3+2*2^2-5*2}}}
{{{y=2*8+2*4-10}}}
{{{y=16+8-10}}}
{{{y=24-10}}}
{{{y=14}}}=> {{{y}}} is not ={{{10}}} when {{{x=2}}},must be: {{{y=14}}}  



find the value of {{{y}}} when {{{x=3}}}. 

{{{y=2*3^3+2*3^2-5*3}}}

{{{y=2*27+2*9-15}}}

{{{y=54+18-15}}}

{{{y=57}}}