Question 1152747
A man has a collection of dimes and quarters with a total of $3.50. If he has 7 more dimes than quarters, how many of each coins does he have?
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Set the "7 more dimes" aside.
Now it's pairs of 1Q & 1D worth $2.80
280/35 = 8 pairs.
+ 7 dimes ---> 8Q & 15D