Question 1152745
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y = {{{16*(x+9)^2 + 7}}} = 16x^2 + 2*16*9x + 16*81 + 7 = 16x^2 + 288x + 1303.


    b = 288,  c = 1303.      <U>ANSWER</U>



{{{graph( 330, 330, -12, 5, -5, 20,
          16*(x+9)^2+7, 16x^2 + 288x + 1303
)}}}


Plot y = 16*(x+9)^2+7 (red) and y = 16x^2 + 288 + 1303 (green)


The two lines COINCIDE, therefore, you see only one of them (the green one, which overlays / over-poses the red line).
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Solved.