Question 1152725

{{{(2^(sin^2(x)))(2^(cos^2(x)))(2^(tan^2(x)))=2^2}}}

if base same, add exponents 

{{{2^((sin^2(x)+cos^2(x)+tan^2(x)))=2^2}}}........since {{{sin^2(x)+cos^2(x)=1}}}

{{{2^(1+tan^2(x))=2^2}}}..........since base same, we have

{{{1+tan^2(x)=2}}}

{{{tan^2(x)=2-1}}}

{{{tan^2(x)=1}}}-> {{{tan(x)=1}}} or {{{tan(x)=-1}}}

{{{x=tan^-1(1)}}}

{{{x=pi/4 +pi*n}}} (result in radians)

{{{x=tan^-1(-1)}}}

{{{x= -pi/4+pi*n}}}  (result in radians)