Question 1152727
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Coordinates for the tip of the shorter hand at this time are  ({{{x[1]}}},{{{y[1]}}}) = (4*cos(60°),4*sin(60°)) = ({{{4*(1/2)}}},{{{4*(sqrt(3)/2)}}}) = ({{{2}}},{{{2*sqrt(3)}}}).


Coordinates for the tip of the longer hand at this time are ({{{x[2]}}},{{{y[2]}}}) = (0,6).


Now apply the formula for the distance between two points in a coordinate plane given by their coordinates


    {{{d^2}}} = {{{(x[2]-x[1])^2}}} + {{{(y[2]-y[1])^2}}}.


In your case,  dx = {{{x[2]-x[1]}}} = -2;  dy = {{{y[2]-y[1]}}} = {{{6-2*sqrt(3)}}}.


Therefore,   {{{d^2}}} = {{{(-2)^2}}} + {{{(6-2*sqrt(3))^2}}}.


At this point, I leave it to you to complete calculations.


You just have all needed instructions, and the way is clear.
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Happy calculations (!)