Question 1152692
Let the numbers be x and y
(1) {{{ x - y = 3 }}}
(2) {{{ x*y = 28 }}}
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(1) {{{ x = 3 + y }}}
Plug this result into (2)
(2) {{{ ( 3 + y )*y = 28 }}}
(2) {{{ y^2 + 3y = 28 }}}
(2) {{{ y^2 + 3y - 28 = 0 }}}
(2) {{{ ( y + 7 )*( y - 4 ) = 0 }}} ( by looking at it )
{{{ y = 4 }}} ( I'll use the positive answer )
and
(1) {{{ x - 4 = 3 }}}
(1) {{{ x = 7 }}}
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The numbers are 7 and 4
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check:
(2) {{{ x*y = 28 }}}
(2) {{{ 7*4 = 28 }}}
OK
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Note that {{{ x = -4 }}} , {{{ y = -7 }}}
works also