<PRE><B>Question 106449</B>
the perimeter (2W+2L) of the corral plus 3 interior fences (3W) is 190, so 5W+2L=190 ... let x=length, so (190-2x)/5=width


the area of the corral (LW) plus the 1 m border is 962 ... (x+2)((190-2x+10)/5)=962


(x+2)(200-2x)=5*962 ... 200x-2x^2+400-4x=4810 ... x^2-98x+2205=0


use quadratic formula to find x</PRE>