<PRE><B>Question 1152544</B>
&lt;br&gt;
Here is an unorthodox way of solving the problem that works for me....&lt;br&gt;
(1) Determine the average interest rate, given that 4 times as much was invested at 3% as at 6%:&lt;br&gt;
{{{(4(.03)+1(.06))/5 = 0.036}}}&lt;br&gt;
(2) Determine the total amount invested, given the interest of $1620 and knowing the average interest rate:&lt;br&gt;
{{{0.036(x) = 1620}}}
{{{x = 1620/0.036 = 45000}}}&lt;br&gt;
(3) Divide the total of $45,000 in the ratio 4:1&lt;br&gt;
ANSWER: $36,000 at 3%; $9000 at 6%&lt;br&gt;
CHECK: .03(36000)+.06(9000) = 1080+540 = 1620&lt;br&gt;
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