Question 1152562

if the sum of two numbers, {{{x}}} and {{{y}}}, is {{{60}}}, we have

{{{x+y=60}}}........eq.1


if one number is {{{4 }}}times as large as the other, we have

{{{x=4y}}}.......eq.2

substitute {{{x}}} from eq.2 in eq.1

{{{4y+y=60}}}........eq.1, solve for {{{y}}}

{{{5y=60}}}

{{{y=60/5}}}

{{{y=12}}}

o back to

{{{x=4y}}}.......eq.2, substitute {{{y}}}

{{{x=4*12}}}

{{{x=48}}}




answer: the numbers are {{{12}}} and {{{48}}}