Question 1152469
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To me at least, the wording of the problem is not clear.  It talks about "drawings" and "trials", and I can't figure out whether those are two names for the same thing.<br>
The way I read the problem, 3 balls are drawn ("1st drawing") and then 3 more balls are drawn ("2nd drawing").  And if that is the case, then of course the first drawing can't give 3 white balls and 3 red balls, because the first drawing only draws three balls....<br>
So the probability that the 1st drawing will give 3 white balls and 3 red balls is 0.<br>