Question 1152502
{{{8^0 * 2^(-3)=1*(1/2^3)=1/8}}}

{{{(2^3)^(-2)= 1/((2^3)^2)=1/(2^6)=1/64}}}

{{{(6^(-1))^2=(1/6)^2=1/6^2=1/36}}}

{{{x^(-8)=1/x^8}}}

{{{3*x^(-5)=3*1/x^5=3/x^5}}}