Question 1152429

let one number be {{{x}}} and another {{{y}}}

if one number is {{{10}}} less than {{{three}}}{{{ times }}}another, we have

{{{x=3y-10}}}..........eq.1


if their sum is {{{14}}}, we have

{{{x+y=14}}}.......eq.2

substitute {{{x}}} from eq.1 in eq.2

{{{3y-10+y=14}}}.......eq.2

{{{4y=14+10}}}

{{{4y=24}}}

{{{y=24/4}}}

{{{y=6}}}

go to {{{x=3y-10}}}..........eq.1 substitute {{{y}}} 

{{{x=3*6-10}}}

{{{x=18-10}}}

{{{x=8}}}


 the two numbers are: {{{8}}} and {{{6}}}