<PRE><B>Question 1152349</B>
A woman has a total of $12,000 to invest.
 She invests part of the money in an account that pays 6% per year and the rest in an account that pays 8% per year.
 If the interest earned in the first year is $820, how much did she invest in each account?
:
let a = amt invested at 8%
the total is 12000, therefore
(12000-a) = amt invested at 6%
:
.08a + .06(12000-a) = 820
.08a + 720 - .06a = 820
.08a - .06a = 820 - 720
.02a = 100
a = 100/.02
a = $5000 invested at 8%
then 
12000 - 5000 = $7000 invested at 6%
:
:
:
Check the amt of interest of each
.08(5000) = 400
.06(7000) = 420
----------------
total int: 820



She invested $7000 at 6% and $5000 at 8%.</PRE>