Question 1152329

do you have this:

{{{2^(-x) +1^(x+2)=5}}}

if yes, then

{{{2^(-x) +1^(x+2)=5}}}.....{{{1^(x+2)=1}}} for any value of {{{x}}}

{{{2^(-x) +1=5}}}

{{{2^(-x) =5-1}}}

{{{2^(-x) =4}}}

{{{2^(-x) =2^2}}}-> if base same, exponents are same too

{{{-x =2}}}

{{{x =-2}}}-> solution


check:

{{{2^(-(-2)) +1^(-2+2)=5}}}

{{{2^2 +1^0=5}}}

{{{4 +1=5}}}

{{{5=5}}}


if you have something else, describe it or post picture