Question 106323
{{{x+4y = 2}}}
put this in the form {{{y = mx + b}}}
{{{4y = -x + 2}}}
{{{y = (-1/4)x + (1/2)}}}
In this form, m is the slope
{{{m = -(1/4)}}}
Any parallel line has the same slope, so the line I want is
{{{y = (-1/4)x + b}}}
Now I have to find {{{b}}}
The line I'm looking for goes through (-1,3)
{{{3 = (-1/4)(-1) + b}}}
{{{3 = 1/4 + b}}}
{{{b = 3 - (1/4)}}}
{{{b = 12/4 - 1/4}}}
{{{b = 11/4}}}
So, my line is
{{{y = (-1/4)x + 11/4}}}
or
{{{4y = -x + 11}}}
{{{x + 4y = 11}}} answer