Question 1152237
{{{ 8/60 = 1/15 }}} hrs is the 1st car's head start
Let {{{ d }}} = distance in miles the car travels 
until it catches the truck
Let {{{ t }}} = time in hrs the car takes to catch the truck
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Equation for truck:
(1) {{{ d - 60*(1/15) = 60t }}}
Equation for car:
(2) {{{ d = 73t }}}
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(1) {{{ 73t - 60*(1/15) = 60t }}}
(1) {{{ 13t = 4 }}}
(1) {{{ t = 4/13 }}} hrs
{{{ ( 4/13)*60 = 18.46 }}}
The car passes the truck in 18.46 minutes
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check:
(2) {{{ d = 73t }}}
(2) {{{ d = 73*(4/13) }}}
(2) {{{ d = 22.46 }}} mi
and
(1) {{{ d - 60*(1/15) = 60t }}}
(1) {{{ d - 60*(1/15) = 60*(4/13) }}}
(1) {{{ d - 4 = 18.4615 }}}
(1) {{{ d = 22.46 }}} mi
OK
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