Question 1152224
find three consecutive even integers such that the product of the first and third is 18 greater than the product of -1 and the third.
<pre>Let 1st integer be F
Then the 2nd and 3rd are: F + 2, and F + 4, respectively
Then we get the following equation: F(F + 4) = - 1(F + 4) + 18
{{{matrix(3,3, F^2 + 4F, "=", - F - 4 + 18,
F^2 + 4F + F - 14, "=", 0,
F^2 + 5F - 14, "=", 0)}}}
(F - 2)(F + 7) = 0
F, or 1st integer = 2             OR              F = - 7 (ignore)
You should be able to list the other 2 now!
Note that the other person is WRONG, as usual!