Question 1152202

if its a dice then the odds are  {{{5/6=0.8333}}}

explanation:

The are {{{1}}},{{{2}}},{{{3}}},{{{4}}},{{{5}}},{{{6}}}, each one with a probability of {{{1/6}}}. 

How many are larger than {{{1}}}? 
Answer is :{{{2}}},{{{3}}},{{{4}}},{{{5}}}, and {{{6}}} 

That means we can add the probability of each one (we do not have to subtract anything since they are independent) so we end up with

{{{1/6+1/6+1/6+1/6 +1/6=5/6= 0.8333}}}