Question 1152170
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There is no such equation.<br>
The given points give us 3 equations:<br>
(1) {{{2 = b^(k-2)}}}
(2) {{{3 = b^k}}}
(3) {{{6 = b^(k+1)}}}<br>
Equations (1) and (2) together give us<br>
{{{b^k/b^(k-2) = b^2 = 3/2}}}  -->  {{{b = sqrt(3/2)}}}<br>
Equations (2) and (3) together give us<br>
{{{b^(k+1)/b^k = b = 2}}}<br>