Question 1152190

pattern:

The next number is the sum of the previous {{{3}}} numbers
So:
If we start with {{{1}}},{{{1}}},{{{1}}} next one is {{{1+1+1 = 3}}}
We have {{{1}}},{{{1}}},{{{1}}},{{{3}}} next one is {{{1+1+3 = 5}}}
We have: {{{1}}},{{{1}}},{{{1}}},{{{3}}} ,{{{5 }}}next one is {{{1+3+5 = 9}}}
We have: {{{1}}},{{{1}}},{{{1}}},{{{3}}} ,{{{5 }}},{{{9}}} next one is {{{3+5+9 = 17}}}
We have: {{{1}}},{{{1}}},{{{1}}},{{{3}}} ,{{{5 }}},{{{9}}},{{{17}}} next one is {{{5+9+17 = 31}}}

We have: {{{1}}},{{{1}}},{{{1}}},{{{3}}} ,{{{5 }}},{{{9}}},{{{17}}},{{{31}}} next one is {{{9+17+31 = 57}}}
We have: {{{1}}},{{{1}}},{{{1}}},{{{3}}} ,{{{5 }}},{{{9}}},{{{17}}},{{{31}}} ,{{{57}}} next one is {{{17+31+57 = 105}}}

We have: {{{1}}},{{{1}}},{{{1}}},{{{3}}} ,{{{5 }}},{{{9}}},{{{17}}},{{{31}}} ,{{{57}}} ,{{{105}}} next one is  {{{31+57+105 = 193}}}

and so on...I hope you will be able to do it up to the 2019th member of this sequence