Question 1152179

write the slope-intercept  form of:

{{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is y-intercept

a slope:{{{m= 1/2}}},
y-intercept:{{{ b= -3}}}

{{{y=(1/2)x-3}}}



and

{{{y=mx+b}}} 

{{{m=2}}} 
point ({{{-1}}}, {{{3}}})

{{{y=mx+b}}} .........substitute slope and coordinates of given point to calculate y-intercept {{{b}}}

{{{3=2(-1)+b}}}
{{{3=-2+b}}}
{{{3+2=b}}}
{{{b=5}}}

then,

{{{y=2x+5}}}