Question 1152172
Find the domain and range of the function: {{{ G(t)=1/(t^2-16) }}}

For the domain, I set the denominator equal to 0 and added 16 to both sides. Then, I took the square root of both sides. This left me with t=4, therefore the domain would be all real numbers except 4. However, this was incorrect... how did I miss the -4 in the domain restriction?

Also, how could I find the range?

Thanks so much!
<pre>You missed it because when you added 16 to both sides to get: {{{matrix(1,3, t^2, "=", 16)}}}, you should've then taken the SQUARE ROOT of both sides to get: {{{highlight_green(matrix(1,7, sqrt(t^2), "=", " "+- sqrt(16), "====>", t, "=", " "+- 4))}}}
Many individuals forget that when the square root is taken of both sides of an equation, the side WITHOUT the square SHOULD include the <b>±</b> sign.