<PRE><B>Question 1152163</B>
 Given that n is the first of three consecutive numbers and the sum of three numbers exceeds the square of the first number by 5.
Express this information in an equation.
:
n + (n+1) + (n+2)  =  n^2 + 5
Combine like terms
3n + 3 = n^2 + 5
Arrange as a quadratic equation
0 = n^2 - 3n + 5 - 3
n^2 - 3n + 2 = 0
:
:
Can be solved by factoring: (n-1)(n-2)
n = 1, n = 2</PRE>