Question 1152169
{{{ y = b^( x + k ) }}}
(-2,3)
(-1,1)
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(1) {{{ 3 = b^( -2 + k ) }}}
(2) {{{ 1 = b^( -1 + k ) }}}
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(1) {{{ log( 3 ) = ( -2 + k )*log( b ) }}}
(1) {{{ log( b ) = log( 3 ) / ( -2 + k ) }}}
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(2) {{{ log(1) = ( -1 + k )*log( b ) }}}
(2) {{{ 0 = ( -1 + 1 )*log( b ) }}}
{{{ k = 1 }}}
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(1) {{{ 3 = b^( -2 + k ) }}}
(1) {{{ 3 = b^( -2 + 1 ) }}}
(1) {{{ 3 = b^( -1 ) }}}
(1) {{{ b = 1/3 }}}
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The equation is:
{{{ y = b^( x + k ) }}}
{{{ y = (1/3)^( x + 1 ) }}}
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check:
( -2,3 )
{{{ 3 = (1/3)^( -2 + 1 ) }}}
{{{ 3 = ( 1/3 )^(-1) }}}
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( -1,1 )
{{{ 1 = (1/3)^( -1 + 1 ) }}}
{{{ 1 = ( 1/3 )^0 }}}
{{{ 1 = 1 }}}
OK