Question 1152159
on the return flight, the plane cruised at 289 kph for 10 hours.
rate * time = distance.
on the return flight, this equation becomes:
289 * 10 = 2890 kilometers.
on the flight going, this equation becomes:
214 * x = 2890
solve for x to get x = 2890 / 214 = 13.5046729 hours.
that's your solution.
you used the return flight to find the distance.
then you used the distance to find the time of the going flight.