Question 1152118

it given that:

{{{n[1]=50}}}, {{{x[1]=30}}}

=> {{{p[1]=x[1]/n[1]=30/50=0.6}}}




{{{n[2]=50}}}, {{{x[2]=15}}}

=> {{{p[2]=x[2]/n[2]=15/50=0.3}}}




The {{{95}}}% confidence interval is:

{{{CI=((0.6-0.3)+-z*sqrt(0.6(1-0.6)/50+0.3(1-0.3)/50))}}}

from standard normal table, the value of {{{z}}} for {{{95}}}% confidence level is {{{1.96}}}

{{{CI= (0.3+-1.96*sqrt(0.009))}}}
{{{CI= (0.3+-1.96*0.0948683)}}}
{{{CI= (0.3+-0.185941868)}}}

{{{CI= 0.486}}} or {{{CI= 0.114}}}


answer: B) ({{{0.114}}}, {{{0.486}}})