Question 1152108
A square plot of land has a building {{{80ft}}} long and {{{40ft}}} wide at one corner. 

a building is{{{80ft}}} long and {{{40ft}}}=>{{{A=80ft*40ft}}}=>{{{A[1]=3200ft^2}}}

The rest of the land outside the building forms a parking lot. 

If the parking lot has area {{{A[2]=8900ft^2}}}, what are the dimensions of the entire plot of land?

given that plot is square, the length and width are same: {{{a}}}

total area of a square plot is : {{{a^2}}} and it is = area of a building + area of a parking lot

{{{a^2=A[1]+A[2]}}} 

{{{a^2=3200ft^2+8900ft^2}}}

{{{a^2=12100ft^2}}}

{{{a=sqrt(12100ft^2)}}}

{{{a=110ft}}}


then parking lot have dimensions: 
{{{a-40=110-40=70}}} 
and {{{a-80=110-80=30}}} 

{{{drawing ( 600, 600, -10, 10, -10, 10,
circle(0,8,.12),circle(8,0,.12),circle(8,8,.12),
line(0,8,8,8),line(8,0,8,8),
line(3,0,3,3),line(3,3,8,3),blue(line(3,0,3,3)), locate(2.5,2,40ft),locate(5,4,80ft),locate(1,-1,30ft),locate(4,7.6,a=110ft),locate(7.5,6,70ft),locate(7.5,2,40ft),locate(5,-1,80ft),
graph( 600, 600, -10, 10, -10, 10, 0)) }}}


{{{A[2]=8900ft^2}}}

{{{70*80+110*30=8900ft^2}}}

{{{5600+3300=8900ft^2}}}