Question 106373
I need to know what A and B are so that logA/logB = 2/3. 
----------
The "change of base rule" says logA/logB = log(baseB)A
----------
So your equation becomes 
log(base B)A = 2/3
-------------
Writing that in exponential form you get:
A = B(2/3)
------------
Therefore B = A(3/2)
====================
Cheers,
Stan H.