Question 1152046
What are the angle measure of the triangle if the measures are 

{{{a=21}}}
{{{b=7sqrt(3)=12.12}}}
{{{c=14sqrt(3)=24.25}}}



Angle ∠ {{{A =cos^-1((b^2+c^2-a^2)/2bc)}}}


Angle ∠ {{{A =cos^-1((12.12^2+24.25^2-21^2)/(2*12.12*24.25))}}}


Angle ∠ {{{A =cos^-1(293.96/587.82)}}}


Angle ∠ {{{A =1.04711}}} rad

Angle ∠ {{{A =59.995}}}° = {{{59}}}°{{{59}}}'{{{41}}}"....round it

Angle ∠ {{{A =60}}}° 



Angle ∠ {{{B = cos^-1((a^2+c^2-b^2)/2ac)}}}

 
Angle ∠ {{{B  =cos^-1((21^2+24.25^2-12.12^2)/(2*21*24.25))}}}

 
Angle ∠ {{{B  =cos^-1(882.17/1018.5)}}}


Angle ∠ {{{B  =0.52336}}} rad

Angle ∠ {{{B  =29.986}}}° = {{{29}}}°{{{59}}}'{{{11}}}"......round it

Angle ∠ {{{B  =30}}}°


Angle ∠ {{{C =cos^-1((a^2+b^2-c^2)/2ab)}}}


Angle ∠ {{{C =cos^-1((21^2+12.12^2-24.25^2)/(2*21*12.12))}}}


Angle ∠ {{{C =cos^-1(-0.1681/509.04)}}}


Angle ∠ {{{C =1.57113}}} rad

Angle ∠ {{{C = 90.019}}}° = {{{90}}}°{{{1}}}'{{{8}}}"......round it


Angle ∠ {{{C = 90}}}°