Question 1151986
X=0,1,2,...,25 for a binomial distribution with n=25 and p=0.2

E(X)=25*0.2=5
probability of at least 2 correct answers is 1- p(0) and p(1)
the probability of 0 is 0.8^25=0.0038
prob of 1 is 25*0.2*0.8^24=0.0236
That sum is 0.0274, so probability of at least 2 is 1-0.0274 or 0.9726.