Question 1152037

the line that passes through ({{{-2}}},{{{-2}}}) and has a slope {{{m = -2}}}

use point-slope formula

{{{y-y[1]=m(x-x[1])}}}.........substitute given values

{{{y-(-2)=-2(x-(-2))}}}

{{{y+2=-2(x+2)}}}

{{{y+2=-2x-4}}}

{{{y=-2x-4-2}}}

{{{y=-2x-6}}}=> your equation


{{{drawing( 600, 600, -10, 10, -10, 10,
circle(-2,-2,.12),locate(-2,-2,p(-2,-2)),
 graph( 600, 600, -10, 10, -10, 10, -2x-6)) }}}