Question 1152015

{{{-(1/2)y-2=x-4}}}....both sides multiply by {{{2}}} to get rid of fraction

{{{-y-4=2x-8}}}

{{{-y=2x-8+4}}}

{{{-y=2x-4}}}....both sides multiply by {{{-1}}} to get {{{y}}} positive

{{{y=-2x+4 }}}=> the slope-intercept form


Then graph the {{{inequality}}}??? you have the {{{equality}}}

since you have linear equation,  graph will be a line, you need two points


make table

{{{x}}}|{{{y}}}

{{{0}}}|{{{4}}}.......{{{y=-2*0+4=4 }}}

{{{2}}}|{{{0}}}.......{{{0=-2x+4 }}}=>{{{2x=4}}}=>{{{x=2}}}

plot these points and draw a line through


{{{drawing ( 600, 600, -10, 10, -10, 10,

graph( 600, 600, -10, 10, -10, 10,-2x+4)) }}}



find if the points ({{{4}}}, {{{4}}}) satisfy the equality


{{{y=-2x+4 }}}......if {{{x=4}}} and {{{y=4}}}, we have

{{{4=-2*4+4 }}}

{{{4=-8+4 }}}

{{{4=-4 }}}=> false

so, the point ({{{4}}}, {{{4}}}) does not satisfy the equality