Question 15665
 the general expression for odd integer is 2n+1...since ..n is any integer, 2n is always even . if we add one to an even number we get an odd number
  so let the first odd integer be 2n+1 
  the second point to be noted is that consecutive odd integers  differ by 2 .
  ( like 1,3,5 etc..)..so now 
   1st. number = 2n+1
    2nd.no.=2n+3
  3rd.no. = 2n+5
  4th.no. = 2n+7
  5th. no. =2n+9
sum of 1st and 5th. nos .=2n+1+2n+9=4n+10.......(1)

  three times the 4th. no. = 3*(2n+7)=6n+21
  one less than above = 6n+21-1 = 6n+20.....(2)
  (1) = (2) ....so 4n+10=6n+20
    4n-6n=20-10=10
-2n=10
n=-5...so the five nos.are 
  1st. number = 2n+1 = 2(*-5)+1 = -9
    2nd.no.=2n+3................=-7
  3rd.no. = 2n+5................=-5
  4th.no. = 2n+7................=-3
  5th. no. =2n+9................=-1