Question 1151997

let two numbers be {{{x}}} and {{{y}}}

if the average of two numbers is {{{11}}},we have

{{{(x+y)/2=11}}}

{{{x+y=11*2}}}

{{{x+y=22}}}

{{{x=22-y}}}.........eq.1


if the difference between them is {{{4}}}, we have

{{{x-y=4}}}

{{{x=y+4}}}......eq.2


from eq.1 and eq.2 we have

{{{22-y=y+4}}}

{{{22-4=y+y}}}

{{{2y=18}}}

{{{y=18/2}}}

{{{y=9}}}


then, 

{{{x=9+4}}}......eq.2

{{{x=13}}}

answer: your numbers are: {{{9}}} and {{{13}}}