Question 1151811
A= 25 degrees
a=5
b=11
Solve the triangle ABC
Use the law of sine to find angle B: {{{a/sin(A)}}} = {{{b/sin(B)}}} = {{{c/sin(C)}}}
{{{11/sin(B)}}} = {{{5/sin(25)}}}
cross multiply
5*sin(B) = sin(25)*11
5*sin(B) = 4.6488
sin(B) = {{{4.6488/5}}}
B = 68.40 degrees
:
Find C:
180 - 25 - 64.4 = 86.6 degrees
:
Find c
{{{c/sin(86.6)}}} = {{{5/sin(25)}}}
c = sin(86.6)*11.83
c = 11.81 the length of side c