Question 106347
Jo has 37coins( all nickels, dimes and quaters) worth $5.50. She has 4 more quarters than nickels. How many dimes does Jo have?
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Let number of nickels be "x" ; value of these is 5x cents
Number of quarters is "x+4" ; value of these is 25(x+4)=25x+100 cents
Number of dimes = 37-x-(x+4)=33-2x; value is 10(33-2x)=330-20x cents
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EQUATION:
value + value + value = 550 cents
5x + 25x+100 + 330-20x = 550
10x = 120
x = 12 (number of nickels)
x+4 = 16 (number of quarters)
37-12-16=9 (number of dimes)
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Cheers,
Stan H.