Question 1151748


Amanda invests ${{{25000}}} 

part {{{x}}} at {{{5}}}% and the rest{{{25000-x}}}   at {{{6}}}%

 The annual return on the {{{5}}}%={{{0.05}}} investment exceeds the annual return on the {{{6}}}%={{{0.06}}} investment by ${{{40}}}.

so, 

{{{0.05x = 0.06*(25000 - x) + 40}}}

{{{0.05x = 1500 - 0.06x+ 40}}}

{{{0.05x+ 0.06x= 1540 }}}

{{{0.11x= 1540 }}}

{{{x= 1540/0.11 }}}

{{{x= 14000 }}}


so, {{{14000}}} is invested at {{{5}}}% and {{{25000-14000=11000}}}   at {{{6}}}%



check interest difference: 

{{{5}}}%={{{0.05}}} of {{{14000}}} is: {{{14000*0.05=700}}}
{{{6}}}%={{{0.06}}} of {{{11000}}} is: {{{11000*0.06=660}}}

{{{700-660=40}}}-> which confirms our solution