Question 1151681
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Because the x occurs both as a linear term and as a term to the power c, you can't solve the general equation for x.<br>
For the value c=1, solving the equation is simple:<br>
x = a-bx^1
x = a-bx
x+bx = a
x(1+b) = a
x = a/(1+b)<br>
And you could also solve the equation if c=2:<br>
x = a-bx^2
bx^2+x-a = 0
Then use the quadratic formula....<br>
But for other values of c, the given equation can't be solved for x.<br>