Question 106315
{{{6A^2x^2-11Ax=10}}}Original equation
{{{6A^2x^2-11Ax-10=0}}}Use the additive inverse of 10.
{{{(2Ax-5)*(3Ax+2)=0}}}Factor the quadratic equation. 
First solution
{{{(2Ax-5)=0}}}
{{{2Ax=5}}}
{{{highlight(x=5/(2A))}}}
Second solution
{{{(3Ax+2)=0}}}
{{{3Ax=-2}}}
{{{highlight(x=-2/(3A))}}}
Check your answers.
{{{6A^2x^2-11Ax=10}}}
{{{6A^2(5/(2A))^2-11A(5/(2A))=10}}}
{{{6A^2(25/(4A^2))-55/2=10}}}
{{{75/2-55/2=10}}}
{{{10=10}}}
Good answer.
{{{6A^2x^2-11Ax=10}}}
{{{6A^2(-2/(3A))^2-11A(-2/(3A))=10}}}
{{{6A^2(4/9A^2)+22/3=10}}}
{{{8/3+22/3=10}}}
{{{10=10}}}
Good answer.