Question 106311
The parabola is already in vertex form:
{{{y=a(x-h)^2+k}}}
where (h,k) is the vertex.
{{{y=x^2-2}}}
{{{y=(1)(x-0)^2-2}}}
the vertex is (0,-2) 
{{{ graph( 300, 300, -5, 5, -5, 5, x^2-2) }}}