Question 1151555
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<pre>

According to the condition, the number of rods sold as a function of price "p" is


    n(p) = 90 + {{{(5/10)*(200-p)}}},   

or, equivalently,

    n(p) = 90 + 0.5*(200-p).


The revenue R(p)  as the function of price is then the product


    R(p) = p*n(p) = p*(90 + 0.5*(200-p) = p*(90 + 100 - 0.5*p) = -0.5p^2 + 190p.


To generate the revenue of 17600 dollars, the price should satisfy this equation


    R(p) = 17600 dollars,

or, equivalently

    -0.5p^2 + 190p = 17600.


Simplify and solve for p.


    p^2 - 380p + 35200 = 0

    {{{p[1,2]}}} = {{{(380 +- sqrt(3800^2 - 4*35200))/2}}} = {{{(380 +- 60)/2}}}.


<U>ANSWER</U>.  There are two solutions: p= 160  and  p= 220  dollars.
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Solved.