Question 1151508
so you have {{{75}}} as the width of the red octagon
since there is a {{{2cm}}} boarder around,means you will have to add {{{2cm}}} to the left and {{{2cm}}} to the right of the red octagon

so, a total of {{{4cm}}} is added to {{{75}}} which gives you a total width of {{{79cm}}}  

now using a scale of {{{14}}} we will get proportionally smaller image:

{{{79cm/14 = 5.64cm}}}

so.the width of the red octagon, to nearest tenth is {{{5.6cm}}}

since given that the inside red portion is {{{75cm}}}

{{{75cm/14=5.357cm}}}

so, to nearest tenth is {{{5.4cm}}}

answer : 

the ENTIRE width of an image of the stop sign is __ {{{5.6}}} ___cm.
the width of the INSIDE red portion is __{{{5.4cm}}}____cm