Question 1151486
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The perimeter of a rectangle is twice the length plus twice the width.  (When you walk around the perimeter of a rectangular field, you travel the length twice and the width twice.)<br>
So half the perimeter is the length plus the width once each.  (When you walk halfway around that rectangular field, you walk the length once and the width once.)<br>
The given perimeter is 320m, so half the perimeter is 160m.<br>
That 160m is the length (95m) plus the width; so the width is 160-95 = 65m.<br>
With formal algebra, that solution looks something like this:<br>
{{{P = 2L+2W = 320}}}
{{{L+W = 160}}}
{{{95+W = 160}}}
{{{W = 65}}}<br>