Question 1151414
In the expansion of {{{(x + 4y)^12}}}, the numerical coefficient of the 5th term is

5th term= {{{nC(r-1)*x^(n-r+1)*(4y)^(r-1) }}}where {{{n=12}}}, {{{r=5}}}


5th term= {{{12C(5-1)*x^(12-5+1)*(4y)^(5-1) }}}


5th term= {{{12C4*x^8*(4y)^4}}}


5th term= {{{(12!/((12-4)!4!))*x^8*256y^4}}}  


5th term= {{{495*x^8*256y^4}}}


5th term= ‭{{{126720x^8*y^4}}}